for k,v in targets.iteritems():
    price= str(v['stockprice'])

    Bids = str(u''.join(v['OtherBids']))
    Bids = Bids.split(',')

    # create a list of unique bids by ranking
    for a,b in zip(float(price),Bids):
        try:
            del b[next(i for i,e in enumerate(b) if format(e,'.4f')  == a)]
        except StopIteration:
            pass

我从我的字典中提取数据,但似乎所有这些都是unicode.我怎么能摆脱unicode废话？

解决方法

我认为你的代码是给你错误信息,TypeError：zip参数#1必须支持迭代.由于表达式zip(float(price),Bids),您收到此错误.此简化代码演示了错误：

>>> price = str(u'12.3456')
>>> bids = ['1.0','2.0']
>>> zip(float(price),bids)
Traceback (most recent call last):
  File "<stdin>",line 1,in <module>
TypeError: zip argument #1 must support iteration

Python 2.x zip() built-in library function要求其所有参数都是可迭代的. float(price)不是可迭代的.

如果要将float(price)与数组Bids的每个元素组合在一起,可以在第一个参数表达式中使用itertools.repeat().

>>> import itertools
>>> price = str(u'12.3456')
>>> bids = ['1.0','2.0']
>>> zip(itertools.repeat(float(price),len(bids)),bids)
[(12.345599999999999,'1.0'),(12.345599999999999,'2.0')]

我没有看到你使用Unicode数据类型与TypeError有关.